Home
Class 11
MATHS
Suppose n ( >=3) persons are sitting in ...

Suppose `n ( >=3)` persons are sitting in a row. Two of them are selected at random. The probability that they are not together is (A) `1- 2/n` (B) `2/(n-1)` (C) `1- 1/n` (D) nonoe of these

A

`1-2/n`

B

`2/(n-1)`

C

`1-1/n`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

persons are sitting in a row.Two of them are selected.Write the probability that they are together.

There are n person sitting in a row two of them are selected at random the probability that two selected persons are not together is

There are m persons sitting in a row.Two of the mare selected at random.The probability that the two selected persons are together

(n>=5) persons are sitting in a row.Three of these are selected at random.The probability that no two of the selected persons sit together is

Statement-1: 20 persons are sitting in a row. Two of these persons are selected at random. The probability that the two selected persons are not together is 0.9. Statement-2 :If overline(A) denotes the negation of an event A, then P(overline(A))=1-P(A) .

Suppose n ( ge 3) persons are arranged in a row. The probability that two particular persons are not together is

The number of terms in the expansion of (x+1/x+1)^n is (A) 2n (B) 2n+1 (C) 2n-1 (D) none of these

Seven persons are to be seated in a row.The probability that two particular persons sit next to each other is (A) (1)/(3) (B) (1)/(6)(C)(2)/(7) (D) (1)/(2)

n letters are written to n different persons and addresses on the n envelopes are also written. If the letters are placed in the envelopes at random,the probability that at least one letter is not placed in the right envelope,is (A) 1-(1)/(n) (B) 1-(1)/(2n) (C) 1-(1)/(n^(2))(D)1-(1)/(n!)