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For three events A, B and C, P (Exactly ...

For three events A, B and C, P (Exactly one of A or B occurs)
= P (Exactly one of B or C occurs)
= P (Exactly one of C or A occurs) = `(1)/(4)` and
P(All the three events occurs simultaneously = `(1)/(16)`.
Then the probability that at least one of the events occurs, is :

A

`3/10`

B

`7/32`

C

`7/16`

D

`7/64`

Text Solution

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The correct Answer is:
C
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