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For a frequency distribution the mean de...

For a frequency distribution the mean deviation about mean is computed by

A

M.D. `=(sumd)/(sumf)`

B

M.D. `=(sumfd)/(sumf)`

C

M.D. `=(sumf|d|)/(sumf)`

D

M.D. `=(sumf)/(sumf|d|)`

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The correct Answer is:
C
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