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Let F1(A,B,C)=(A^^~B)vv[~C^^(AvvB)]vv~A ...

Let `F_1(A,B,C)=(A^^~B)vv[~C^^(AvvB)]vv~A and F_2(A,B)=(AvvB)vv(BrarrA)` be two logical expressions. Then :

A

`F_1 and F_2` both are tautologies

B

`F_1` is a tautology but `F_2` is not a tautology

C

`F_1` is not tautology but `F_2` is a tautology

D

Both `F_1` and `F_2` are not tautologies

Text Solution

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The correct Answer is:
C
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