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If A=[[i, 0], [0, (i)/(2)]], then A^(-1)...

If `A=[[i, 0], [0, (i)/(2)]]`, then `A^(-1)=`

A

`[(i,0),(0,i//2)]`

B

`[(-i,0),(0,-2i)]`

C

`[(i,0),(0,2i)]`

D

`[(0,i),(2i,0)]`

Text Solution

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The correct Answer is:
B
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