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For what value of lambda, the system of ...

For what value of `lambda`, the system of equations `x+y+z=6,x+2y+3z=10,x+2y+lambdaz=12` is inconsistent

A

`lambda=1`

B

`lambda=2`

C

`lambda=-2`

D

`lambda=3`

Text Solution

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The correct Answer is:
To determine the value of \( \lambda \) for which the system of equations is inconsistent, we need to analyze the given equations: 1. \( x + y + z = 6 \) (Equation 1) 2. \( x + 2y + 3z = 10 \) (Equation 2) 3. \( x + 2y + \lambda z = 12 \) (Equation 3) ### Step 1: Write the system in matrix form We can represent the system of equations in matrix form as \( A \mathbf{x} = \mathbf{b} \), where: \[ A = \begin{bmatrix} 1 & 1 & 1 \\ 1 & 2 & 3 \\ 1 & 2 & \lambda \end{bmatrix}, \quad \mathbf{x} = \begin{bmatrix} x \\ y \\ z \end{bmatrix}, \quad \mathbf{b} = \begin{bmatrix} 6 \\ 10 \\ 12 \end{bmatrix} \] ### Step 2: Calculate the determinant of matrix \( A \) To find the value of \( \lambda \) that makes the system inconsistent, we need to find the determinant of matrix \( A \) and set it equal to zero: \[ \text{det}(A) = \begin{vmatrix} 1 & 1 & 1 \\ 1 & 2 & 3 \\ 1 & 2 & \lambda \end{vmatrix} \] ### Step 3: Expand the determinant Using the first row to expand the determinant: \[ \text{det}(A) = 1 \cdot \begin{vmatrix} 2 & 3 \\ 2 & \lambda \end{vmatrix} - 1 \cdot \begin{vmatrix} 1 & 3 \\ 1 & \lambda \end{vmatrix} + 1 \cdot \begin{vmatrix} 1 & 2 \\ 1 & 2 \end{vmatrix} \] Calculating each of these 2x2 determinants: 1. \( \begin{vmatrix} 2 & 3 \\ 2 & \lambda \end{vmatrix} = 2\lambda - 6 \) 2. \( \begin{vmatrix} 1 & 3 \\ 1 & \lambda \end{vmatrix} = \lambda - 3 \) 3. \( \begin{vmatrix} 1 & 2 \\ 1 & 2 \end{vmatrix} = 0 \) Putting it all together: \[ \text{det}(A) = (2\lambda - 6) - (\lambda - 3) + 0 \] ### Step 4: Simplify the determinant Now simplify the expression: \[ \text{det}(A) = 2\lambda - 6 - \lambda + 3 = \lambda - 3 \] ### Step 5: Set the determinant to zero For the system to be inconsistent, the determinant must equal zero: \[ \lambda - 3 = 0 \] ### Step 6: Solve for \( \lambda \) Solving for \( \lambda \): \[ \lambda = 3 \] ### Conclusion The value of \( \lambda \) for which the system of equations is inconsistent is \( \lambda = 3 \). ---
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