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Given P = (3,-6,10)and PQ = sqrt(17) . I...

Given `P = (3,-6,10)and PQ = sqrt(17)` . If direction cosines of line PQ are ` (-2)/(sqrt(17)),3/(sqrt(17)),(-2)/(sqrt(17))` , then point Q can be

A

(1,-2,4)

B

(2,5,8)

C

(-1,3,-8)

D

(1,-3,8)

Text Solution

Verified by Experts

The correct Answer is:
D
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