Home
Class 12
MATHS
The equation of the plane which passes t...

The equation of the plane which passes through (2,-3,1) and is normal to the line joining the points (3,4,-1) and (2,-1,5) is given by

A

x+5y-6z+19=0

B

x-5y+6z-19=0

C

x+5+6z+19=0

D

x-5y-6z-19=0

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

If a plane passes through the point (-3,-3,1) and is normal to the line joining the points (2,6,1) and (1,3,0), find its equation.

Find the equation in Cartesian form of the plane passing through the point (3,\ -3,\ 1) and normal to the line joining the points (3, 4, -1) and (2, -1, 5).

Find the equation of the plane passing through the point (1,2,1) and perpendicular to the line joining the points (1,4,2) and (2,3,5) . find also the perpendicular distance of the origin from this plane.

Find the equation of the plane which passes through the points (6,2,-4) and (3,-4,1) and is parallel to the line joining the points (1,0,3) and (-1,2,4) .

find the equation of the plane passing through the point (3,3,1) and perpendicular to the line joining (3,4,-1) and (2,-1,5).

The equation of the plane passing through (3,2,-1) and normal tot the line (2,1,2) and (4,3,-1) is