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The distance of line 3y - 2z - 1 = 0 = 3...

The distance of line `3y - 2z - 1 = 0 = 3x - z + 4` from the point (2, -1, 6) is :

A

`2sqrt5`

B

`2 sqrt 6`

C

`sqrt(26)`

D

`4 sqrt2`

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The correct Answer is:
B
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