If angleA=90^(@) in the DeltaABC , then...

If `angleA=90^(@)` in the `DeltaABC` , then `tan^(-1)((c)/(a+b))+tan^(-1)((b)/(a+c))` is equal to

A

0

B

1

C

`pi//4`

D

`pi//6`

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The correct Answer is:

C

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