Home
Class 12
MATHS
A particle moves in a straight line so t...

A particle moves in a straight line so that it covers distance `at^(3)+bt+5` meter in t seconds. If its acceleration after 4 seconds is 48 `" meters/sec"^(2)`, then a=

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A point moves in a straight line so that its displacement x metre at a time t second is such that t=(x^2 −1) ^1/2 . Its acceleration in m/s^2 at time t second is:

A particle is moving in a straight line such that the distance covered by it in t seconds from a point is ((t^(3))/(3)-t) cm. find its speed at t=3 seconds.

A particle moves in a straight line, so that after t second, the distance x from a fixed point O on the line is given by x=(l-2)^(2)(t-5) . Then

A particle moves along a straight line in such a way that its acceleration is increasing at the rate of 2 m//s^(3) . Its initial acceleration and velocity were zero. Then, the distance which it will cover in the 3^(rd) second (t=2 " to "t =3 " sec") is :

A particle moves in a straight line with constant acceleration If it covers 10 m in first second and 20 m in next second find its initial velocity.

A particle moves along straight line for 10 second with unifrom acceleration, a = 2 ms^(-2) . Then for next 10 second moves with acceleration, a = 4 ms^(-1) . The total displacement of particle would be (initial velocity of particle is zero)

The displacement of a particle moving in a straight line is given by s=t^(3)-6t^(2)+3t+4 meters.The velocity when acceleration is zero is "

Position of a particle moving in a straight line is given as y = 3t^3 + t^2 (y in cm and t in second) then find acceleration of particle at t = 2sec