d/(dx)[cos(1-x^2)^2]=...

`d/(dx)[cos(1-x^2)^2]=`

A

`-2x(1-x^2) sin(1-x^2)^2`

B

`-4x (1-x^2) sin (1-x^2)^2`

C

`4x(1-x^2) sin(1-x^2)^2`

D

`-2(1-x^2) sin(1-x^2)^2`

Verified by Experts

The correct Answer is:

C

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