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Let f(x)=(x-7)^2 (x-2)^7, x in [2,7]. th...

Let `f(x)=(x-7)^2 (x-2)^7, x in [2,7].` the value of `theta in (2,7)` such that `f'(theta)=0` is equal to

A

`49//4`

B

`53//9`

C

`53//7`

D

`49//9`

Text Solution

Verified by Experts

The correct Answer is:
B
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