if x^2 e^y + 2 xye^x + 13 =0 then dy...

if ` x^2 e^y + 2 xye^x + 13 =0` then ` dy //dx` =

A

`(2xe^(y-x) +2y(x+1))/(x(xe^(y-x) +2))`

B

`(2xe^(x-y) +2y(x+1))/(x(xe^(y-x) +2))`

C

`-(2xe^(y-x) +2y(x+1))/(x(xe^(y-x) +2))`

D

None of these

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

If x^(2)e^(y)+2xye^(x)+13=0 then (dy)/(dx)=

If y=log(e^(x^2)) , then dy/dx=?

If y=e^(x^2+logx) , then dy/dx=?

If y=e^(x)x^(2) then (dy)/(dx)=

If y =e^(xsin 2x +cos 2x ), then (dy)/(dx) =

If x log_(e) (log _(e) x) - x^(2) + y^(2) = 4 (y gt 0) , then (dy)/(dx) at x = e is equal to

If x^(3) dy + xy dx = x^(2) dy + 2y dx , y (2) = e and x gt 1 , then y(4) is equal to .

2e^(x+2y) dx -3dy =0

If y=e^(3x+2) ,then (dy)/(dx) is

If x^(2y)=e^(x-y)," then "(dy)/(dx)=