(d)/(dx)[tan^(-1)((ax-b)/(bx+a))]=...

`(d)/(dx)[tan^(-1)((ax-b)/(bx+a))]=`

A

`(1)/(1+x^2) -(a^2)/( a^2 +b^2)`

B

`(-1)/(1+x^2) -(a^2)/(a^2 +b^2)`

C

`(1)/(1+x^2) +(a^2)/(a^2+b^2)`

D

None of these

Verified by Experts

The correct Answer is:

D

Similar Questions

Explore conceptually related problems

int_(-1)^(1)(d)/(dx)[tan^(-1)((1)/(x))]dx=

(d)/(dx)[tan^(-1)((6x)/(1+7x^(2)))]+(d)/(dx)[tan^(-1)((5+2x)/(2-5x))]=

(d)/(dx)[tan^(-1)((sinx)/(1+cosx))]=

At x=(pi)/(4),(d)/(dx)[tan^(-1)((cosx)/(1+sinx))]=

(d)/(dx)[sec(tan^(-1)x)]=

(d)/(dx)[tan^(-1)((1)/(2x)-(x)/(2))]=

(d)/(dx)[tan^(-1)((10x)/(4-6x^(2)))]=

(d)/(dx)[tan{tan^(-1)((x)/(a))-tan^(-1)((x-a)/(x+a))}]=

d/(dx)[tan^(-1)((a-x)/(1+ax))] is equal to

(d)/(dx)[tan^(-1)((asinx+bcosx)/(acosx-bsinx))]=