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If x = exp {tan^(-1)((y-x^2)/(x^2))} the...

If `x = exp {tan^(-1)((y-x^2)/(x^2))}` then dy/dx equals

A

`2x[1+tan (logx)] + x sec^2 (log x)`

B

`x[1+tan (logx)] + sec^2 (log x)`

C

`2x[1+tan (logx)] + x^2 sec^2 (log x)`

D

`2x[1+tan (logx)] + sec^2 (log x)`

Text Solution

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The correct Answer is:
A
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