The curve x^3 - 3xy^2 + 2 = 0 and 3x^2 y...

The curve `x^3 - 3xy^2 + 2 = 0` and `3x^2 y-y^3 -2= 0` cut at an angle of

A

`pi/4`

B

`pi/3`

C

`pi/2`

D

`pi/6`

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

The two curves x^(3)-3xy^(2)+2=0 and 3x^(2)y-y^(3)-2=0

The two curves x^(3)-3xy^(2)+5=0 and 3x^(2)y-y^(3)-7=0

The curves x^(3) -3xy^(2) = a and 3x^(2)y -y^(3)=b, where a and b are constants, cut each other at an angle of

Show that the curve x^(3)-3xy^(2)=a and 3x^(2)y-y^(3)=b cut each other orthogonally, where a and b are constants.

The curve x^(2)+2xy-y^(2)-x-y=0 cuts the x -axis at (0,0) at an angle

The curve x^(2)+2xy-y^(2)-x-y+1=0 cuts the x -axis at (0,0) at an angle

The curve x^(4)-2xy+y+3x3y=0 cuts the x -axis at (0,0) at an angle