Home
Class 12
MATHS
The function f(x) =e^(ax) +e^(-ax), agt ...

The function f(x) =`e^(ax) +e^(-ax), agt 0` is monotonically increasing for

A

`-1 lt x lt 1`

B

`x lt -1`

C

`x gt -1`

D

`x gt 0`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

If a<0, the function f(x)=e^(ax)+e^(-ax) is a monotonically decreasing function for values of x given by

Find the value of a for which the function f(x) =x^(2)-2ax+6,x gt 0 is strictly increasing.

If a le 0 f(x) =e^(ax)+e^(-ax) and S={x:f(x) is monotonically increasing then S equals

Find the possible values of a such that f(x)=e^(2x)-(a+1)e^(x)+2x is monotonically increasing for x in R.

Find possible values of 'a' such that f(x) =e^(2x) -2(a^(2) -21) e^(x)+ 8x+5 is monotonically increasing for x in R.

If the function f(x)=(x^(2))/(2)+ln x+ax is always monotonically increasing in its domain then the least value of a is 2(b)-2(c)-1(d)1

The function f(x)=x^(2)e^(-x) is monotonic increasing when (a) x in R-[0,2](b)^(@)0

The function f(x)=xsqrt(ax-x^2), a lt 0

The function f(x)= (x^(2))/(e^(x)) monotonically increasing if