Home
Class 12
MATHS
The value of c in (0, 2) satisfying the ...

The value of c in (0, 2) satisfying the mean value theorem for the function `f(x)=x (x-1)^(2), x in [0,2]` is equa to

A

`3/4`

B

`4/3`

C

`1/3`

D

`2/3`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The value of c in (0,2) satisfying the Mean Value theorem for the function f(x)=x(x-1)^(2), x epsilon[0,2] is equal to

Verify mean value theorem for the function f(x) = x^(3)-2x^(2)-x+3 in [0,1]

Verify mean value theorem for the function f(x)=sqrt(25-x^(2)) in [1,5]

If mean value theorem holds for the function f(x)=(x-1)(x-2)(x-3), x in [0,4], then c=

The value of c in mean value theorem for the function f(x)= x^2 in [2,4] is

The value of c in Largrange's mean value theorem for the function f(x)=x(x-2) when x in [1,2] is

The value of c in the Lagrange's mean value theorem for the function f(x)=x^(3)-4x^(2)+8x+11 , when x in [0, 1] is :

Verify mean value theorem for the function f(x)=x^(2)+4x-3 in the interval [-2,2]

Verify Lagranges mean value theorem for function f(x)=x^2-3x+2 on [-1,\ 2]