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int"cosec"(x-a)"cosec"xdx is equal to...

`int"cosec"(x-a)"cosec"xdx` is equal to

A

`(1)/(sin a) log ( sin (x-a)"cosec"x]+C`

B

`(1)/(sin a )log [ sin (x-a) sin x]+C`

C

`(-1)/(sin a ) log | sin x "cosec " (x-a)|+C`

D

`(-1)/( sin a ) log [ sin (x-a)sin x ]+C`

Text Solution

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The correct Answer is:
A
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