int[f(x)g''(x)-f''(x)g(x)] dx is equal ...

`int[f(x)g''(x)-f''(x)g(x)]` dx is equal to

A

`(f(x))/(g'(x))`

B

`f'(x) g(x) - (f(x) g'(x)`

C

`f(x)g'(x) -f'(x) g(x)`

D

`f(x) g'(x) + f ' (x) g (x)`

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The correct Answer is:

C

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