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The integral intcos(log(e)x)dx is equal ...

The integral `intcos(log_(e)x)dx` is equal to: (where C is a constant of integration)

A

`x[ cos (log_e x)- sin (log_e x)]+c`

B

`(x)/(2) [ sin (log _x)+sin (log_e x)]+c`

C

`x[cos (log_e x )+ sin (log _e x)]+c`

D

`(X)/(2) [ cos (log_e x) + sin (log_e x)]+c`

Text Solution

Verified by Experts

The correct Answer is:
D
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