int cos 2 theta.ln((costheta+sintheta)/(...

`int cos 2 theta.ln((costheta+sintheta)/(costheta-sintheta)) d theta`

A

`(cos theta - sin theta)^2 log ((cos theta + sin theta )/(cos theta - sin theta))`

B

`(cos theta + sin theta)^2 log ((cos theta + sin theta )/(cos theta - sin theta))`

C

`((cos theta + sin theta)^2)/(2) log ((cos theta + sin theta )/(cos theta - sin theta))`

D

`1/2 sin 2 theta log tan ((pi)/(4)+ theta)-1/2 log sec 2 theta `

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The correct Answer is:

D

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