int(0)^(lambda) (ydy)/(sqrt(y+lambda)) ...

` int_(0)^(lambda) (ydy)/(sqrt(y+lambda))` is equal to

A

`2/3 (2 - sqrt2) lambda sqrt lambda `

B

`2/3 (2 + sqrt2) lambda sqrt lambda`

C

`1/3 (2 - sqrt2 ) lambda sqrt lambda`

D

`1/3(2 + sqrt 2) lambda sqrt lambda`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

lim_(lambda rarr0)(int_(0)^(1)(1+x)^(lambda)dx)^((1)/(lambda)) is equal to

A= [{:(0,3),(2,0):}] and A^(-1)=lambda (adj, A) then lambda is equal to

int_ (0) ^ (1) (xdx) / (sqrt (x + lambda) + sqrt (x + mu)), lambda! = mu

If lambda is a root of x^(2) + 3x + 1 = 0 then tan^(-1) lambda+ tan^(-1) (1/lambda) is equal to

If int_(0)^(1)cot^(-1)(1-x+x^(2))dx=lambda int_(0)^(1)tan^(-1)xdx, then lambda is equal to 1( b) 2(c)3(d)4

If int(e^(x)(2-x^(2)))/((1-x)sqrt(1-x^(2)))dx=mu e^(x)((1+x)/(1-x))^(lambda)+C , then 2(lambda+mu) is equal to ..... .

If (x+y)^(2)=2(x^(2)+y^(2)) and (xy+lambda)^(2)=4,lambda>0, then lambda is equal to