The area bounded by the curves y=sqrtx, ...

The area bounded by the curves `y=sqrtx, 2y-x+3=0,` X-axis and lying in the first quadrant is

A

`9`

B

`27/4`

C

`36`

D

`18`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

The area bounded by the curves y=sqrt(x),2y-x+3=0, X-axis and lying in the first quadrant is

The area (in square units) bounded by the curves y=sqrt(x),2y-x+3=0, x-axis, and lying in the first quadrant is

Find the area of the region bounded by the curve y = sqrt ( 36 - x ^(2)), the X- axis lying in the first quadrant and the lines X= 0, X = 6 ?

Find the area of the region bounded by the curve x = sqrt (25 - y ^(2)) , the Y- axis lying in the first quadrant and the lines y =0 and y =5.

Find the area bounded by the curves y=sqrt(x),2y+3=x and x -axis.

The area bounded by the curve y = sin2x, axis and y=1, is

The area bounded by the curve y^(2)=9x and the lines x=1,x=4 and y=0, in the first quadrant,is