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f(x)=int0^x e^t f(t)dt+e^x , f(x) is a d...

`f(x)=int_0^x e^t f(t)dt+e^x , f(x)` is a differentiable function on `x in R` then `f(x)=`

A

`2e^((e^x -1)) - 1`

B

`e^(e^x) - 1`

C

`2e^(e^x) - 1`

D

`e^((e^x - 1))`

Text Solution

Verified by Experts

The correct Answer is:
A
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