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The general solution of differential equ...

The general solution of differential equation `(e^x + 1)ydy = (y + 1)e^xdx` is

A

`c(y+1) (e^x +1) +e^y=0`

B

`c(y+1) (e^x -1) +e^y=0`

C

`c(y+1) (e^x -1) -e^y=0`

D

`c(y+1) (e^x +1) -e^y`=0

Text Solution

Verified by Experts

The correct Answer is:
D
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