Home
Class 12
MATHS
Let in a Binomial distribution, consisti...

Let in a Binomial distribution, consisting of 5 independent trials, probalitiies of exactly 1 and 2 sucesses be 0.4096 and 0.2048 resepectively. Then the probability of getting exactly 3 sucesses is equal to :

A

`(80)/(243)`

B

`(40)/(243)`

C

`(32)/(625)`

D

`(128)/(625)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

There are 5 independent trials , probability of exactly one success is 0.4096 , probability of exactly 2 success is 0.2048 . Find probability of exactly 3 success

The mean and varaince of binomial distribution are 4 and 3, respectively. Then, the probability of getting exactly six success in this distribution is

Three different coins are tossed together.Find the probability of getting (1) exactly 2 heads (2) atleast 2 heads

The probabilities of A, B, C solving a question are (1)/(3),(2)/(7) and (3)/(8) respectively. Find the probability that exactly one of them will solve it.

A fair coin is tossed at a fixed number of xx.If the probability of getting exactly 3 headsequals the probability of getting exactly 5 heads,then the probability of getting exactlyone head is

A and B are two independent events such that their probabilities are (3)/(10) " and " (2)/(5) respectively. The probability of exactly one of the events happening, is

For a binomial distribution the mean is 6 and the standard deviation is sqrt(2) . Find the probability of getting 5 successes .