If velocity of a particle increases 5m/s per meter, then find acceleration of the particle at instant when velocity become 20m/s

In a linear S.H.M., the acceleration of the particle is zero, when its velocity is

. If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is

If the velocity of a particle is (10+2t^(2)m/s ,then the average acceleration of the particle between 2s and 5s is (in m/s^2)

A particle is given an initial speed inside a fixed smooth spherical shell of radius 1 m such that just able to complete the vertical circle acceleration of particle at instant when velocity becomes perpendicular to initial (initially particle at the bottom)

The velocity of a particle at an instant is 10m/s. After 5sec, the velocity of the particle is 20m/s. Find the velocity at 3 seconds before from the instant when velocity of a particle is 10m/s.

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

A particle performs linear S.H.M. At a particular instant, velocity of the particle is 'u' and acceleration is ' prop ' while at another instant, velocity is 'v' and acceleration ' beta ' (0ltpropltbeta) . The distance between the two position is

A particle experience an acceleration a=(4e^(-3t))m/s^(2) along positive x-axis, where t is time in s .If the initial velocity of the particle is 2m/s along positive x-axis,the velocity of the particle when its acceleration becomes zero is?