In SHM, v-x graph will be...

In SHM, v-x graph will be

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In SHM, graph of which of the following is a straight line?

In S.H.M., the graph between kinetic energy K and time 't' is

A particle is performing linear S.H.M. If the acceleration and corresponding velocity of the particle are prop and v respectively and if we plot v^2 on Y axis and prop^2 on X axis, then the graph will be

STATEMENT-1 : A particle is performing simple harmonic motion along X axis with amplitude A . If a graph is plotted between velocity of particle and its X coordinate then graph will be elliptical. STATEMENT-2 : Velocity of particle in SHM as a fuction of position is given by v=omegasqrt(A^(2)-X^(2)).

The displacement -time (x– t) graph of a body is given as The corresponding velocity -time (v – t ) graph will be

Part of SHM is graphed in the figure. Here, y is displacement from mean position. The correct equation describing the SHM is

If a graph is plotted between velocity (v) and displacement (y) of a particle executing SHM from mean position, then the nature of the graph is

Depict the shown v-x graph in a-x graph :

In the above problem if given graph is between V_(AB) and time. Then plot graph between V_(ED) and time.

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