Temperature of 7 moles of a monoatomic gas is raised by 40K. The change in internal energy of sample is equal to .......R

Method 1 of DeltaU Temperature of two moles of a monoatomic gas is increased by 600 K in a given process. Find change in internal energy of the gas.

The internal energy of one mole of a gas is

Temperature of four moles of a monoatomic gas is increased by 300K in isochoric process. Find W, Q and DeltaU .

The internal energy of a perfect monoatomic gas is

V-T graph of a process of monoatomic ideal gas is shown in figure. Change in internal energy of the gas is zero in process(s)-

Enthalpy of 1 mole monoatomic ideal gas is equals to :-

The temperature of a sample of a gas is raised from 127^(@)C to 527^(@)C .The average kinetic energy of the gas

For an ideal gas, (i) the change in internal energy in a constant pressure process from temperature T_1 to T_2 is equal to nC_V(T_2-T_1) , where C_V is the molar heat capacity at constant volume and n is the number of moles of the gas (ii) The change in internal enregy of the gas and the work done by the gas are equal in magnitude in an adiabatic process. (iii) The internal energy does not change in an isothermal process. ltbr. (iv) no heat is added or removed in an adiabatic process

When "1" mole of an ideal monoatomic gas is compressed adiabatically the internal energy change involved is "24 cals.The temperature rise is

When 1 mole of an ideal monoatomic gas is compressed adiabatically the internal energy change involved is 24 cals. The temperature rise (in kelwin) is