Let f:R rarr Rbe differentiable at x = 0...

Let `f:R rarr R`be differentiable at x = 0. If f(0) = 0 and `f'(0)=2`, then the value of
`lim_(xrarr0)(1)/(x)[f(x)+f(2x)+f(3x)+….+f(2015x)]` is

A

2015

B

0(zero)

C

`2015xx2016`

D

`2015xx2014`

Verified by Experts

The correct Answer is:

C

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