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f(x)=([729p(1+x)]^(1/7)-3)/([729(1+qx)]^...

`f(x)=([729p(1+x)]^(1/7)-3)/([729(1+qx)]^(1/3)-9), and f(x)` is continuous at `x=0` , then

A

`21qf(0)-p=0`

B

`21q^2f(0)-p^3=0`

C

`21p^2f(0)-q^3=0`

D

`p^2f(0)-7q^2=0`

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