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If (p^(**)q) odot (p odot ~q) is tautolo...

If `(p^(**)q) odot (p odot ~q)` is tautology then ordered pair `(odot ,^(**))` is

A

`(wedge ,vv)`

B

`(vv ,vv)`

C

`(vv,wedge)`

D

`(wedge ,wedge)`

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