Solve `2cos^2theta+sinthetalt=2,` where `pi/2lt=thetalt=(3pi)/2dot`

Options

A. `x in [(pi)/2,(5pi)/6)`
B. `x in ((pi)/2,(5pi)/6)uu[pi,(3pi)/2]`
C. `x in [(pi)/2,2pi]uu[pi,(3pi)/2]`
D. `x in [(pi)/2,(5pi)/6]uu[pi,(3pi)/2]`

Answer

D