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(p wedge q) to (p wedge r) is equivalent...

`(p wedge q) to (p wedge r)` is equivalent to

A

`~(p wedge q) to r`

B

`(p wedge q) to q`

C

`(p wedge q) to p`

D

`( p vv q) to r`

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The correct Answer is:
A
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