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(Part-2) Concept of center of mass l Ashu sir l #science #sciencefun #physics

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One end of a thin uniform rod of length L and mass M_(1) is rivetted to the center of a uniform circular disc of radius r and mass M_(2) so that both are coplanar. The center of mass of the combination from the center of the disc is (Assume that the point of attachment is at the origin) 1) L ( M_(1) + M_(2) ) // 2 M_(1) 2) L M_(1) // 2 ( M_(1) + M_(2) ) 3) 2 ( M_(1) + M_(2) ) // L M_(1) 4) 2 L M_(1) // ( M_(1) + M_(2) )

A drum major's baton consists of two masses m_(1) and m_(2) separated by a thin rod length l. The baton is thrown into the air. The problem is to find the baton's center of mass and the equation of motion for the center of mass.

A thin uniform bar of length L and mass 8m lies on a smooth horizontal table .Two point masses m and 2 m are moving in the same horizontal plane from opposite sides of the bar with speeds 2v and v respectively .The masses stick to the bar after collision at a distances (L)/(3) and (L)/(6) respectively from the center of the bar if the bar starts rotating about its center of mass as result of collision the angular speed of the bar will be

In the figure, the L- shaped shaded piece is cut from a metal plate of uniform thickness. The point that corresponding to the center of mass of the L- shapped piece is :-

A small square loop of wire of side l is placed inside a large square loop of wire of side L(L>>l) .The loops are coplanar and their centers coincide.The mutual inductance of the system is proportional to

The four particles of masses m , 3m, 2m and 4m are placed on the vertices of a sqare of side L . Locate the center of mass

A vessel is partitioned in two equal halves by a fixed diathermic separator. Two different ideal gases ae filled in left (L) and right (R) halves the rms speed of the molecules in L part is equal to the mean speed of moleucles in the R equal to the ratio of the mass of a molecules in L part to that of a molecules in R part is

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