A particle is projected with a velocity v, so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is :

Options

A. `(4v^(2))/(5g)`
B. `(4g)/(5v^(2))`
C. `(4v^(3))/(5g^(2))`
D. `(4v)/(5g^(2))`

Answer

A