A particle is projected from the ground with an initial speed of v at an angle `theta` with horizontal. The average velocity of the particle between its point of projection and highest point of trajectroy is :

Options

A. `v/2sqrt(1+2 cos^(2) theta)`
B. `v/2sqrt(1+2 cos^(2) theta)`
C. `v/2sqrt(1+3 cos^(2) theta)`
D. `vcos theta`

Answer

C