B2B plus B2C Business #shorts #b2b #b2c #business #b2bplusb2cbusiness

Suppose A, B, C are defined as A=a^2b+a b^2-a^2c-a c^2, B=b^2c+b c^2-a^2b-a b^2, a n dC=a^2c+a c^2-b^2c-b c^2, w h e r ea > b > c >0 and the equation A x^2+B x+C=0 has equal roots, then a ,b ,c are in AdotPdot b. GdotPdot c. HdotPdot d. AdotGdotPdot

If the arthmetic mean of (b-c)^2, (c-a)^2 and (a-b)^2 is the same as that of (b+c-2a)^2, (c+a-2b)^2 and (a+b-2c)^2 show that a=b=c .

If a/b , b/c , c/a are in H.P., then (a)a^2b,c^2a,b^2c are in A.P. (b)a^2b, b^2c,C62a are in H.P. (c)a^2b,b^2c,c^2a are in G.P. (d) none

In a triangle ABC, if a, b, c are in A.P. and (b)/(c) sin 2C + (c)/(b) sin 2B + (b)/(a) sin 2A + (a)/(b) sin 2B = 2 , then find the value of sin B

In Q.No 126,c= (a) b (b) 2b (c) 2b^(2)(d)-2b

In a triangle ABC, if a,b,c are in A.P and (b)/(c)sin2C+(c)/(b)sin2B+(b)/(a)sin2A+(a)/(b)sin2B=2 then the value of sin B equals

If a,b,c are in G.P., then show that : (a^2-b^2)(b^2+c^2)=(b^2-c^2)(a^2+b^2)

If A=2B, then prove that either c=b or a^(2)=b(c+b)