concept of apparent weight

The apparent weight of man inside a lift moving up with certain acceleration is 600N. When the lift is coming down with the same acceleration apparent weight is found to be 200N.The mass of the man is ?(g=10m s^(-2) )

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

Assertion : When the lift moves with uniform velocity the man in the lift will feel weightlessness. Reason : In downward accelerated motion of lift, apparent weight of a body decreases.

For a body floating on water, apparent weight is equal to :

Explain how the apparent weight of a person, taking a ride in a roller-coaster varies.

A Person stood in an accelerating elevartor. Explain how the apparent weight of this person varies.

A body weights 5 kg in air. Calculate the apparent weight of the body in water if its density is 2000 kg//m^(3) .

A man of weight W is standing on a lift which is moving upward with an acceleration a. The apparent weight of the man is