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Show that the force of attraction between two short magnets of moment m and m' with their centres d distance apart and their axes in the same direction along the same lines is (mu_(0))/(4pi) (6mm')/(d^(4))

Important Time Saving Short Trick / Shortcut For JEE Main 2019 Maths

Two short electric dipoles of moment P and 8P are placed in opposite direction on a line at a distance of 15cm .The electric field will be zero at point between the dipoles whose distance from the dipole of moment P is?

Application OF Equilibrium Constant | | Determination OF direction OF reaction | | Extent OF Reaction | | Equilibrium Concentration | | Class Illustrations with Short Tricks

Important Time Saving Short Trick / Shortcut For JEE Main 2019 Maths | Part 2

Important Time Saving Short Trick / Shortcut For JEE Main 2019 Maths | Part - 4

A short bar magnet has a magnetic moment of 0.65TJ ^(-1) , then the magnitude and direction of the magnetic field produced by the magnet at a distance 8 cm from the centre of magnet on the axis is

JEE MAINS Short Tricks | Shortcut To Solve Integration | Maths Time Saving Tricks |JEE Mains 2020