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There is one short magnet of magnetic moment 2.16 Am^2 , which is placed on horizontal surface with its North Pole pointing towards north. Locate null point on horizontal surface if horizontal component of earth's magnetic field is 27 mu t .

A short bar magnet is placed with its north pole pointin north. The neutral point is 10 cm away from the centre of the magnet. If H=0.4G , calculate the magnetic moment of the magnet.

A short bar magnet is placed with its north pole pointing south. The neutral point is 10cm away from the centre of the magnet. If H=0*4 gauss, calculate magnetic moment of the magnet.

The horizontal component of the earth's magnetic field at a place is 3.0 X 10^(-4) T and the dip is 53^@ . A metal rod of length 25cm is placed in the north - south direction and is moved at a constant speed of 10cm s^(-1) towards east. Calculate the emf induced in the rod.

A short bar magnet is placed in the magnetic meridian of the earth with its north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East-West line drawn through the mid point of the magnet. What is the magnetic moment of the magnet in Am^(2) ? (Given m=10^(-7) in SJ units and B_(H)= horizontal component of earth's magnetic field =3.6xx10^(-5) tesla)