The equilibrium constant K c for the fol...

The equilibrium constant K c for the following reaction at 842°C is `7.90 × 10^( –3)` . What is `K_(p)` at same temperature?
`1/2F_(2)harr(g)F(g)`

A

`8.64 × 10^(–5)`

B

`8.26 × 10^(–4)`

C

`7.90 × 10^(–2)`

D

`7.56 × 10^(–2)`

लिखित उत्तर

Verified by Experts

The correct Answer is:

D

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