The equilibrium constant for the reaction `N_(2) (g) + O_(2) (g) harr2NO(g)` at temperature (T) is `4 × 10^( –4)` . The value of `K_(c)` for the reaction `NO(g)harr1/2N_(2) (g) + 1/2O_(2)` at the same temperature is:

Options

A. `4 × 10^(–4)`
B. 50
C. `2.5x10^(2)`
D. 0.02

Answer

B