The equilibrium constant (`K_(c)` ) for the reaction
`2HCl(g) harrH_(2) (g) + Cl_(2) (g)`
is `4 × 10^(–34)` at 25°C. What is the equilibrium constant for the reaction?
`1/2H_(2) (g) + 1/2Cl_(2) (g)harrHCl(g)`

Options

A. `2 × 10^ (–17)`
B. `2.5 × 10^(33)`
C. `5 × 10^(6)`
D. None of these

Answer

D