Using valence bond theory, explain the following in relation to the complexes given below
`[Mn(CN)_(6)]^(3-), [Co(NH_(3))_(6)]^(3+), [Cr(H_(2)O)_(6)]^(3+), [FeCl_(6)]^(4-)`
(a) type of hybridisation
(b) Inner or outer orbital complex
(c) Magnetic behaviour
(d) Spin only magnetic moment value.

Amongst the following , the most stable complex is : (a) [Fe(H_(2)O)_(6)]^(3+) (b) [Fe(NH_(3))_(6)]^(3+) (c) [Fe(C_(2)O_(4))_(3)]^(3-) (d) [FeCl_(6)]^(3-) .

One the basis of VBT answer the following complex ions (i) [Ti(bpy)_(3)]^(Θ) (b) [V(H_(2)O)_(6)]^(3+) (ii) [V(H_(2)O)_(6)]^(3+) (III) [Mn(CN)_(6)]^(4-) [Mn(CN)_(6))]^(3-) (V) [Ir(NH_(3))_(6)]^(3+) . Type of hybridisation involed (b) Type of inner or outer orbital octahedral complex (c ) Magnetic behaviour and mu_(spin) value .

The magnetic moment of complex given below are in the order: (I) [Ni(CO)_(4)] (II) [Mn(CN)_(6)]^(4-) (III) [Cr(NH_(3))_(6)]^(3+) (IV) [CoF_(6)]^(3-)

Consider the following complex ions. [CrCl_(6)]^(3-)" "[Cr(H_(2)O)_(6)]^(3+) [Cr(NH_(3))_(6)]^(3+)" "[Cr(CN)_(6)]^(3-) The correct order of triangle_(0) is :

Given complexes are low spin complexes [V(CN)_(6)]^(4-) [Cr(NH_(3))_(6)]^(3+) [Ru(NH_(3))_(6)]^(3+) [Fe(CN)_(6)]^(4-) Then of magnetic (mu) for V^(2+), Fe^(2+), Cr^(3+), Ru^(3+) is

In the complex [Fe(H_(2)O)_(6)]^(3+) [Fe(CN)_(6)]^(3-) [Fe(C_(2)O_(4))_(3)]^(3-) and [FeCl_(6)]^(3-) , that complex that has highest stability is

The magnetic moment of a complex ion is 2.83BM The complex ion is [Cr(H_(2))O)_(6)]^(3+) (b) [Cu(CN)_(6)]^(2-) (c ) [V(H_(2)O))_(6)]^(3+) (d) [MnCI_(4)]^(2-) .