Given `[CS_(2)]` = 0.120 M, `[H_(2)]` = 0.10, `[H_(2)S]` = 0.20 and `[CH_(4)] = 8.40 × 10 ^(–5)` M for the following reaction at 900°C, at eq. Calculate the equilibrium constant (`K_(c)` ):

Options

A. 0.012
B. 0.098
C. 0.28
D. 0.12

Answer

C