3 कमाल Smartphone Charging Tips For Better Battery Life *AMAZING* #shorts

A constant current exists in an inductor coil connected to a battery. The coil is short circuited and the battery is removed. Show that the charge flown through the coil aftter the short circuiting is the same as that which flows in one time constant before the short circuiting.

Capacitor C_1 is connected to a battery and charged till the magnitude of the charge on each plate is q_0 . Then, the battery is disconnected and C_1 is connected to two other uncharged capacitors C_2 and C_3 as shown in figure. Final charges on the capacitors (q_1,q_2 and q_3) are related by .

When an ammeter of negligible internal resistance is inserted in series with circuit, it reads 1 A . When a voltmeter of very large resistance is connected across R_(1) , it reads 3 V . But when the points A and B are short-circuited by a conducting wire, then the voltmetre measures 10.5 V across the battery. The internal resistance of the battery is equal to

Two capacitors C_(1)=3muF and C_(2)=6muF in series, are connected in parallel to a third capacitor C_(3)=4muF . This arrangement is then connected to a battery of e.m.f., = 30V , as shown. The energy lost by the battery in charging the capacitors

Extended Wheatstone Bridge||Charging-Discharging of Battery||Short-Circuit of Resistance||Short-Circuit of Battery

A battery is used to charge a parallel plate combination of two identical capacitors. If the potential difference across the battery is V and the total charge Q flows through the battery during the charging process then 1) The charge on each capacitor is Q/2 and the potential of each capacitor is V/2 2) The charge on each capacitor is Q and the potential of each capacitor is V 3) The charge on each capacitor is Q/2 and the potential of each capacitor is V 4) The charge on each capacitor is Q and the potential of each capacitor is V/2