what is Kinetic energy ( K.E ) ? || #YouTubeshorts

Which of the following statements about kinetic energy (K.E.) is true?

The magnitude of binding energy of the satellite is E and kinetic energy is K. The ratio E/K is

Kinetic energy of a particle on the surface is e_(0) and potential energy is -E_(0)/(2) . (a) Will the particle escape to infinity ? (b) At some height some height its kinetic energy becomes 0.6 E_(0) . What is potential energy at this height ? (c) If the particle escape to infinity , what is kinetic energy of the particle at infinity ?

The kinetic energy (K.E.) of a beam of electrons, accelerated through a potential V, equalws the energy of a photon of wavelength of 5460 nm. Find the de-Broglie wavelength associated with this beam of electrons.

The momentum of a body is p and its kinetic energy is E. Its momentum becomes 2p. Its kinetic energy will be

A body is orbiting very close to the earth surface kinetic energy K.E. The energy required to completely escape from it is

The radius of the orbit of a satellite is r and its kinetic energy is k if the radius of the orbit is doubled then the new kinetic energy k is

Relation between kinetic energy and momentum Let us consider a body of mass 'm' having a velocity 'v', then momentum of the body P = mass xx velocity P = m xx v rArr v = (P)/(m) " "...(1) From definition, kinetic energy (K.E) of the body K.E = (1)/(2) mv^(2)" "...(2) Now putting the value of (1) in (2) we have K.E = (1)/(2)m ((P)/(m))^(2) K.E. = (1)/(2)m (P^(2))/(m^(2)) = (1)/(2) (P^(2))/(m) = (P^(2))/(2m)" "...(3) Thus we can write P^(2) = 2m xx K.E rArr P = sqrt(2m xx K.E) Thus momentum = sqrt(2 xx "mass" xx "kinetic energy") The kinetic energy of a given body is doubled. Its momentum will